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Multiple Choice

What is f(0) given f(x) = 2x + 3?

Evaluating a function at a specific input means substituting that value for x. For f(x) = 2x + 3, plug in x = 0: f(0) = 2(0) + 3 = 3. So the result is 3. The other numbers come from different inputs: 0 would occur if the constant term weren’t present; 2 would be the value of 2x when x is 1 (but with x = 0 you still add 3); 5 is what you get from f(1) = 2(1) + 3. The important point is that the +3 shifts the output up by 3 when x is 0.

Evaluating a function at a specific input means substituting that value for x. For f(x) = 2x + 3, plug in x = 0: f(0) = 2(0) + 3 = 3. So the result is 3. The other numbers come from different inputs: 0 would occur if the constant term weren’t present; 2 would be the value of 2x when x is 1 (but with x = 0 you still add 3); 5 is what you get from f(1) = 2(1) + 3. The important point is that the +3 shifts the output up by 3 when x is 0.