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Multiple Choice

Solve for x: 5x + 3 = 23.

Solving for a variable in a simple linear equation by undoing the operations that were applied to it. Start with 5x + 3 = 23. Remove the added constant by subtracting 3 from both sides, giving 5x = 20. Then undo the multiplication by dividing both sides by 5, which yields x = 4. This works because 5 times 4 equals 20, and 20 plus 3 equals 23, matching the original equation. Checking other values shows they don’t fit: for example, a value of 3 gives 5×3+3 = 18, not 23; 2 gives 13; 5 gives 28. The only value that satisfies the equation is x = 4.

Solving for a variable in a simple linear equation by undoing the operations that were applied to it. Start with 5x + 3 = 23. Remove the added constant by subtracting 3 from both sides, giving 5x = 20. Then undo the multiplication by dividing both sides by 5, which yields x = 4. This works because 5 times 4 equals 20, and 20 plus 3 equals 23, matching the original equation. Checking other values shows they don’t fit: for example, a value of 3 gives 5×3+3 = 18, not 23; 2 gives 13; 5 gives 28. The only value that satisfies the equation is x = 4.