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Multiple Choice

Solve 2x^2 = 32. What are the solutions?

Isolating the squared term and taking square roots is the key step. From 2x^2 = 32, divide both sides by 2 to get x^2 = 16. If x^2 equals 16, x can be either 4 or -4 because squaring either value gives 16. These satisfy the original equation: 2*(4)^2 = 32 and 2*(-4)^2 = 32. Numbers like x = 2 or x = 0 don’t fit, since they produce 8 and 0, respectively. Therefore, the solutions are x = 4 and x = -4.

Isolating the squared term and taking square roots is the key step. From 2x^2 = 32, divide both sides by 2 to get x^2 = 16. If x^2 equals 16, x can be either 4 or -4 because squaring either value gives 16. These satisfy the original equation: 2*(4)^2 = 32 and 2*(-4)^2 = 32. Numbers like x = 2 or x = 0 don’t fit, since they produce 8 and 0, respectively. Therefore, the solutions are x = 4 and x = -4.